Book a tutor

Practical: diffusion and osmosis

Structure and functions in living organisms · Movement of substances into and out of cells · note 5 of 5

Practical: diffusion and osmosisSpec 2.17

In short

Diffusion and osmosis can be investigated with living systems such as potato cylinders and non-living systems such as Visking tubing and agar cubes. Potato cylinders gain mass in dilute solutions and lose mass in concentrated ones because water moves by osmosis. Glucose diffuses through Visking tubing but starch cannot, and small agar cubes change colour fastest.

You need to be able to investigate diffusion and osmosis using living systems (such as potato tissue) and non-living systems (such as Visking tubing and agar).

Living system: osmosis in potato cylinders

Practical:

Independent variable: concentration of the solution; dependent variable: change in mass. Blot each cylinder dry before you weigh it, because surface water adds mass that is not from osmosis.

  1. Use a cork borer to cut cylinders from one potato, and trim them to the same length.
  2. Measure and record the mass of each cylinder.
  3. Put each cylinder in a different concentration of sugar (or salt) solution, including pure water, using the same volume of solution each time.
  4. Leave them for the same length of time at the same temperature.
  5. Remove the cylinders, blot them dry with paper towel and measure their final mass.
  6. Calculate the percentage change in mass for each cylinder and plot a graph of percentage change against concentration.
ResultExplanation
Mass increasesThe solution is more dilute than the cell contents, so water moves into the potato by osmosis
Mass decreasesThe solution is more concentrated than the cell contents, so water moves out of the potato by osmosis
No change in massThe solution has the same concentration as the cell contents, so there is no net movement of water
percentage change = (final mass − initial mass) ÷ initial mass × 100

Percentage change in mass

A potato cylinder has a mass of 3.00 g. After 30 minutes in a salt solution its mass is 2.55 g. Calculate the percentage change in mass.

  1. change in mass = 2.55 − 3.00 = −0.45 g
  2. −0.45 ÷ 3.00 = −0.15
  3. −0.15 × 100 = −15%

Answer: −15% (a loss of 15%)

Where the graph line crosses the x-axis (0% change), the concentration of the solution equals the concentration of the potato cell contents. Control the potato, the size of the cylinders, the volume of the solution, the time and the temperature. Cut on a tile away from your fingers, because cork borers and scalpels are sharp.

Non-living system: Visking tubing

Visking tubing is a partially permeable membrane with tiny pores. It lets small molecules such as water and glucose through, but not large molecules such as starch.

  1. Tie one end of a length of soaked Visking tubing and fill it with a mixture of starch and glucose solution. Tie the other end.
  2. Rinse the outside, then place the tube in a beaker of water.
  3. After about 20 to 30 minutes, test the water in the beaker with Benedict's solution (for glucose) and with iodine solution (for starch).

Typical results: the water in the beaker gives a positive Benedict's test, so glucose has diffused out through the pores. It does not turn blue-black with iodine, so the starch molecules were too large to pass through. To show osmosis, fill the tube with a concentrated sugar solution and place it in water. The tube becomes firmer and gains mass as water moves in.

Non-living system: agar cubes

Agar jelly cubes can show diffusion and the effect of surface area to volume ratio. Make agar containing phenolphthalein indicator and a little dilute sodium hydroxide (an alkali), so it is pink. Cut cubes of different sizes, for example 1 cm, 2 cm and 3 cm. Place each cube in the same volume of dilute hydrochloric acid at the same temperature. As the acid diffuses in, it neutralises the alkali and the indicator turns colourless. Time how long each cube takes to become completely colourless.

Typical results: small cubes, with a larger surface area : volume ratio and a shorter distance to the centre, change colour all the way through sooner than large cubes. Wear eye protection when using acid and alkali.

Left: Visking tubing containing starch and glucose solution in a beaker of water, with glucose diffusing out, water moving in by osmosis and starch too large to pass through. Right: 1 cm, 2 cm and 3 cm agar cubes with pink centres and colourless outer layers in dilute hydrochloric acid, with acid diffusing in and a stopwatch timing until each cube is completely colourless. (opens full size in a new tab)
Non-living models: glucose passes through the pores of Visking tubing but starch cannot; acid diffuses into small agar cubes faster than large ones.

Quick check

  1. Define diffusion.

    Show answer

    The net movement of particles from an area of higher concentration to an area of lower concentration.

  2. What is osmosis?

    Show answer

    The diffusion of water from a dilute solution to a more concentrated solution through a partially permeable membrane.

  3. Which of diffusion, osmosis and active transport needs energy from respiration?

    Show answer

    Active transport.

  4. What happens to the surface area to volume ratio as an organism gets bigger?

    Show answer

    It gets smaller.

  5. Why does a potato cylinder lose mass in a concentrated sugar solution?

    Show answer

    Water moves out of the potato cells into the more concentrated solution by osmosis.

Written and checked against the Edexcel IGCSE Biology (4BI1) specification · Updated October 2026

Frequently asked questions

How does osmosis differ from diffusion?

Osmosis is a special type of diffusion that involves only water moving through a partially permeable membrane. Diffusion is the net movement of any particles, such as oxygen or carbon dioxide, from a higher to a lower concentration. In osmosis, water moves from a dilute solution to a more concentrated solution. Neither process needs energy from respiration.

Why does osmosis not require energy?

Osmosis does not require energy because it is a passive process. Water simply diffuses from a dilute solution to a more concentrated solution through a partially permeable membrane, so no energy from respiration is used. Only active transport, which moves substances against a concentration gradient, needs energy from respiration.

Why is active transport needed in plant roots?

Active transport is needed in plant roots because root hair cells often contain a higher concentration of mineral ions than the soil. Diffusion would move ions out of the cell, so the cells must use energy from respiration to move ions in against the concentration gradient. This lets plants take in ions that are in short supply.

All 5 questions on Movement of substances into and out of cells

Finished movement of substances into and out of cells? Test yourself:Exam questionsFlashcards